H=20t^2-5t^2

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Solution for H=20t^2-5t^2 equation: 



=20H^2-5H^2

We move all terms to the left:

-(20H^2-5H^2)=0

We get rid of parentheses

-20H^2+5H^2=0

We add all the numbers together, and all the variables

-15H^2=0

a = -15; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-15)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$H=\frac{-b}{2a}=\frac{0}{-30}=0$

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